Question

if 0.850 l of a 5.00 m solution of copper(ii) nitrate, cu(no₃)₂, is diluted to a volume of 1.80 l by the addition of water, what is the molarity of the dilute solution? 2.36 m 2.18 m 3.76 m 2.57 m 3.44 m

Explanation:

Step1: Recall dilution formula

$M_1V_1 = M_2V_2$

Step2: Identify given values

$M_1 = 5.00\ M$, $V_1=0.850\ L$, $V_2 = 1.80\ L$

Step3: Solve for $M_2$

$M_2=\frac{M_1V_1}{V_2}=\frac{5.00\ M\times0.850\ L}{1.80\ L}\approx2.36\ M$

Answer:

$2.36\ M$