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327 chemistry prep b unit 2 ch 4 test name: i affirm that i did not giv…

Question

327 chemistry prep b unit 2 ch 4 test name: i affirm that i did not give or receive any unauthorized assistance on this test. initials directions: read each question carefully and completely. please write your name and sign the integrity statement. answer each question fully. show all work when necessary. answers without work will not receive credit. part i: fill in the missing pieces of information in the table below. use the periodic table of elements to help you if needed. isotope name notation protons neutrons electrons mass number atomic number isotopic symbol notation (az notation) 42 99 40 ³⁰zn nickel - 58 28

Explanation:

Step1: Recall atomic - related concepts

The atomic number (Z) is equal to the number of protons. The mass number (A) is the sum of protons and neutrons. In a neutral atom, the number of electrons is equal to the number of protons.

Step2: First row calculations

Given the number of protons \(p = 42\) and mass number \(A=99\). The number of neutrons \(n=A - p=99 - 42 = 57\). The number of electrons \(e = p=42\) (since it's a neutral atom). The atomic number \(Z = 42\) (equal to protons). The element with atomic number 42 is molybdenum (Mo), and the isotopic symbol notation is \(_{42}^{99}\text{Mo}\).

Step3: Second row calculations

Given the isotopic symbol \(_{30}^{70}\text{Zn}\). The number of protons \(p = 30\) (from the sub - script Z). The number of electrons \(e = p = 30\) (neutral atom). The number of neutrons \(n=A - Z=70 - 30 = 40\). The mass number \(A = 70\) (from the super - script A).

Step4: Third row calculations

Given the isotope name "Nickel - 58" and atomic number \(Z = 28\). The number of protons \(p = 28\). The number of electrons \(e = p = 28\) (neutral atom). The mass number \(A = 58\). The number of neutrons \(n=A - Z=58 - 28 = 30\). The isotopic symbol notation is \(_{28}^{58}\text{Ni}\).

Isotope Name notationProtonsNeutronsElectronsMass numberAtomic numberIsotopic Symbol notation (AZ Notation)
Zinc - 703040307030\(_{30}^{70}\text{Zn}\)
Nickel - 582830285828\(_{28}^{58}\text{Ni}\)

Answer:

Isotope Name notationProtonsNeutronsElectronsMass numberAtomic numberIsotopic Symbol notation (AZ Notation)
Zinc - 703040307030\(_{30}^{70}\text{Zn}\)
Nickel - 582830285828\(_{28}^{58}\text{Ni}\)