Question

26
formula 4 points
the equation for the reaction of glucose (c₆h₁₂o₆) with oxygen in respiration is shown below. the heat of the reaction is -2900 kj. how many grams
of glucose do you need to produce 8,886 kj of energy? answer to 4 significant figures.
c₆h₁₂o₆(s) + 6 o₂(g) → 6 co₂(g) + 6 h₂o(l)
table of molar masses
m_{c₆h₁₂o₆} = 180.155 g/mol
m_{co₂} = 44.009 g/mol
m_{o₂} = 31.998 g/mol
m_{h₂o} = 18.015 g/mol
answer

Explanation:

Step1: Calculate moles of glucose

From the reaction, 1 mole of \(C_6H_{12}O_6\) releases 2900 kJ.
Let \(n\) be moles of glucose. Using proportion \(\frac{n}{1}=\frac{8886}{2900}\)
\(n=\frac{8886}{2900}\)

Step2: Calculate mass of glucose

Mass \(m = n\times M\), where \(M = 180.155\ g/mol\)
\(m=\frac{8886}{2900}\times180.155\)
\(m=\frac{8886\times180.155}{2900}\)
\(m=\frac{1600072.33}{2900}\approx551.7\ g\)

Answer:

551.7 g