Question

1. the pressure on a 200 - milliliter sample of co₂(g) at constant temperature is increased from 60 kpa to 120 kpa. what is the new volume of the gas? a) 100 ml b) 300 ml c) 400 ml d) 600 ml

Explanation:

Step1: Identify the relevant gas - law

Boyle's law states that $P_1V_1 = P_2V_2$ for a gas at constant temperature.

Step2: Assign values to variables

Let $P_1 = 60\ kPa$, $V_1=200\ mL$, $P_2 = 120\ kPa$, and $V_2$ be the unknown volume.

Step3: Rearrange the formula to solve for $V_2$

From $P_1V_1 = P_2V_2$, we can get $V_2=\frac{P_1V_1}{P_2}$.

Step4: Substitute the values into the formula

$V_2=\frac{60\ kPa\times200\ mL}{120\ kPa}$.
$V_2 = 100\ mL$.

Answer:

A. 100 mL