Question

1. predict the molecular shape of h2s (1 point) *

linear
bent
trigonal planar
trigonal pyramidal
tetrahedral

1. predict the molecular shape of cs2 (1 point) *

linear
bent
trigonal planar
trigonal pyramidal
tetrahedral

Explanation:

Question 20:

To determine the molecular shape of $\ce{H2S}$, we use the VSEPR theory. The central atom (S) has 6 valence electrons. It forms 2 single bonds with H atoms, using 2 electrons, and has 2 lone pairs (since $6 - 2 = 4$, and 4 electrons make 2 lone pairs). The electron - pair geometry is tetrahedral (4 electron groups: 2 bonding, 2 lone pairs), but the molecular shape (considering only bonding groups) is bent because the lone pairs repel the bonding pairs, distorting the shape from the ideal tetrahedral.

For $\ce{CS2}$, the central atom C has 4 valence electrons. It forms 2 double bonds with S atoms (each double bond uses 4 electrons, but for VSEPR, we count electron groups: each double bond is 1 electron group). So there are 2 electron groups (both bonding), and according to VSEPR theory, a molecule with 2 bonding electron groups and no lone pairs on the central atom has a linear molecular shape.

Answer:

B. Bent

Question 21: