Question

1. according to the law of conservation, how many grams are in the reactant magnesium?

magnesium (2 mg) + oxygen (o₂) → magnesium oxide
reactants
+ 16 g → 40 g
products

Explanation:

Step1: Apply the Law of Conservation of Mass

According to the Law of Conservation of Mass, the mass of reactants equals the mass of products. So, mass of \(Mg\) (reactant) \(+\) mass of \(O_2\) (reactant) \(=\) mass of \(MgO\) (product). Let the mass of \(Mg\) be \(x\). We know \(x + 16=40\).

Step2: Solve for \(x\)

Subtract 16 from both sides of the equation \(x + 16=40\). So, \(x=40 - 16\).

Answer:

\(24\space g\)