Question

12 multiple choice 1 point chromium (iii) oxide cr₂o₃ cro cr₃o cr₃o₂

Explanation:

Step1: Determine the charge of chromium and oxygen

Chromium (III) has a charge of \(+3\) (\(Cr^{3+}\)). Oxygen in oxide has a charge of \(-2\) (\(O^{2 -}\)).

Step2: Use the criss - cross method

To form a neutral compound, we use the criss - cross method. The magnitude of the charge of one ion becomes the subscript of the other ion. So for \(Cr^{3+}\) and \(O^{2 -}\), we get \(Cr_{2}O_{3}\) (since \(3\times2 = 2\times3\) to balance the charges).

Answer:

\(Cr_{2}O_{3}\) (the first option)