Question

1. which of the following has a covalent bond?

a. nabr
b. n₂o
c. also₄
d. lif

1. covalent bonds are generally formed between what sort of elements?

a. ones that form ions easily
b. nonmetals
c. metals
d. a metal and a nonmetal

1. how many total hydrogen (h) atoms are in 4c₆h₁₁oh?

enter a numerical value only.
__________ atoms of hydrogen

1. you are asked to make a model of a carbon atoms structure. how many electrons will you include in its outer energy level?

a. 2
b. 4
c. 6
d. 8

1. why is hydrogen grouped with the alkali metals?

a. because it is a gas
b. because it is a metal
c. because it has one electron in its outer energy level
d. because it does not readily form compounds

Explanation:

11.

• NaBr: Sodium (Na) is a metal, bromine (Br) is a non - metal. They form an ionic bond.
• N₂O: Nitrogen (N) and oxygen (O) are non - metals. Non - metals form covalent bonds by sharing electrons.
• AlSO₄: This formula is incorrect (it should be \(Al_2(SO_4)_3\)). Aluminum (Al) is a metal, and the sulfate group (\(SO_4^{2 -}\)) contains non - metals. But the bond between Al and \(SO_4^{2 -}\) is ionic.
• LiF: Lithium (Li) is a metal, fluorine (F) is a non - metal. They form an ionic bond.

• Option A: Ions are formed in ionic bonds (e.g., between metals and non - metals).
• Option B: Non - metals share electrons to form covalent bonds.
• Option C: Metals usually form metallic bonds (in pure metals) or ionic bonds (with non - metals).
• Option D: A metal and a non - metal form an ionic bond.

In the formula \(C_6H_{11}OH\), the number of H atoms in one molecule is \(11 + 1=12\). For \(4C_6H_{11}OH\), we multiply the number of H atoms in one molecule by 4.

Step - by - Step:

Step1: Calculate H atoms in one molecule

In \(C_6H_{11}OH\), \(H\) atoms \(=11 + 1=12\)

Step2: Calculate H atoms in \(4C_6H_{11}OH\)

Total \(H\) atoms \(=4\times12 = 48\)

Answer:

B. \(N_2O\)

12.