Question

1. what is the total number of atoms of c, o and h in 0.260 mol of glucose, c₆h₁₂o₆?

total # of atoms = 0.260 mol
0.260 mol × 6.022 × 10²³ molecules/mol = 1.56572 × 10²³ molecules
1.56572 × 10²³ molecules × 24 atoms/molecule → 3.757728 × 10²⁴ atoms
3.76 × 10²⁴ atoms
signature:

Explanation:

Step1: Calculate the number of molecules

Use Avogadro's number \(N = n\times N_A\), where \(n = 0.260\space mol\) and \(N_A=6.022\times 10^{23}\space molecules/mol\).

$$N = 0.260\times6.022\times 10^{23}=1.56572\times 10^{23}\space molecules$$

Step2: Calculate the number of atoms per molecule

In a glucose molecule \(C_6H_{12}O_6\), the total number of atoms is \(6 + 12+6=24\) atoms/molecule.

Step3: Calculate the total number of atoms

Multiply the number of molecules by the number of atoms per molecule.

$$N_{total}=1.56572\times 10^{23}\times24 = 3.757728\times 10^{24}\space atoms$$

Answer:

\(3.76\times 10^{24}\space atoms\)