Question

10 g of a solid chemical reacts with a 10 g of a liquid chemical, the reaction bubbles and changes the color of the liquid. the colored liquid weighs 13 g, what can be concluded? the gas produced weighed 13 g the gas produced from the bubbles weighed 5 g the bubbles were evidence of 7 g of matter being destroyed the gas produced weighed 7 g

Explanation:

Step1: Calculate the total mass of reactants

The mass of the solid is \(10\ g\) and the mass of the liquid is \(10\ g\). So the total mass of reactants \(m_{reactants}=10 + 10=20\ g\).

Step2: Calculate the mass of the colored liquid and gas

The mass of the colored liquid is \(13\ g\). Let the mass of the gas be \(m_{gas}\).

Step3: Apply the law of conservation of mass

According to the law of conservation of mass \(m_{reactants}=m_{products}\). The products are the colored liquid and the gas. So \(20=13 + m_{gas}\), then \(m_{gas}=20 - 13=7\ g\).

Answer:

The gas produced weighed \(7\ g\)