Question

zn + 2hcl → zncl₂ + h₂
zn: 65.38 g/mol
a 3.79 l container can hold
0.15 moles h₂ gas. what mass of
zn is required to generate
0.15 mol h₂?
? g zn
hint: use stoichiometry.
mass zn (g)

Explanation:

Step1: Find mole ratio of Zn to H₂

From reaction: 1 mol Zn → 1 mol H₂, ratio = 1:1

Step2: Calculate moles of Zn needed

Moles Zn = moles H₂ = 0.15 mol

Step3: Compute mass of Zn

Mass = moles × molar mass = 0.15 mol × 65.38 g/mol = 9.807 g

Answer:

9.81 (rounded to two decimal places)