Question

if you had 3 ce amplifiers with the following gains $a_{v1} = 10$, $a_{v2} = 8$, $a_{v3} = 5$ and $v_s = 250$ mvrms. solve for the total gain in db $a_v(db)$. round your answer to two decimal places.

answer:

Explanation:

Step1: Find total voltage gain

The total voltage gain \( A_{V_{total}} \) of cascaded amplifiers is the product of individual gains. So, \( A_{V_{total}} = A_{V1} \times A_{V2} \times A_{V3} = 10 \times 8 \times 5 = 400 \).

Step2: Convert to dB

The formula for voltage gain in dB is \( A_{V}(dB) = 20 \log_{10}(A_{V_{total}}) \). Substituting \( A_{V_{total}} = 400 \), we get \( A_{V}(dB) = 20 \log_{10}(400) \). Calculating \( \log_{10}(400) \approx 2.6021 \), then \( 20 \times 2.6021 \approx 52.04 \).

Answer:

52.04