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write expressions for the perimeter and area for the figure. then simpl…

Question

write expressions for the perimeter and area for the figure. then simplify these expressions. assume that all measures are given in inches. the perimeter is ( 20sqrt{5} ) inches. (simplify your answer. type an exact answer, using radicals as needed.) the area is ( square ) square inches. (simplify your answer. type an exact answer, using radicals as needed.)

Explanation:

Step1: Simplify \(\sqrt{125}\)

We know that \(125 = 25\times5\), so \(\sqrt{125}=\sqrt{25\times5}\). Using the property \(\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\) (\(a = 25\), \(b = 5\)), we get \(\sqrt{125}=\sqrt{25}\cdot\sqrt{5}=5\sqrt{5}\).

Step2: Find the perimeter formula and calculate

The perimeter \(P\) of a rectangle is \(P = 2(l + w)\), where \(l=\sqrt{125}+4\) and \(w=\sqrt{125}-4\). Substitute \(l\) and \(w\) into the formula:

$$ LATEXBLOCK0 $$

Since \(\sqrt{125}=5\sqrt{5}\), then \(P = 2\times2\times5\sqrt{5}=20\sqrt{5}\) (this is already given, just for verification).

Step3: Find the area formula and calculate

The area \(A\) of a rectangle is \(A=l\times w\), where \(l=\sqrt{125}+4\) and \(w=\sqrt{125}-4\). Using the formula \((a + b)(a - b)=a^{2}-b^{2}\) (\(a=\sqrt{125}\), \(b = 4\)):

$$ LATEXBLOCK1 $$

Answer:

The area is \(109\) square inches.