Question

write an equation in slope-intercept form of the line that passes through the given points.

x	y
-3	-4
0	-3
3	-2
6	-1

y = \square

Explanation:

Step1: Find the slope (m)

The slope formula is $m = \frac{y_2 - y_1}{x_2 - x_1}$. Let's use the points (0, -3) and (3, -2).
So, $m = \frac{-2 - (-3)}{3 - 0} = \frac{-2 + 3}{3} = \frac{1}{3}$.

Step2: Find the y-intercept (b)

The slope - intercept form is $y = mx + b$. We know that when $x = 0$, $y=-3$ (from the point (0, - 3)). Substituting $x = 0$, $y=-3$ and $m=\frac{1}{3}$ into $y=mx + b$, we get $-3=\frac{1}{3}(0)+b$. So, $b=-3$.

Step3: Write the equation

Substitute $m=\frac{1}{3}$ and $b = - 3$ into the slope - intercept form $y=mx + b$. We get $y=\frac{1}{3}x-3$.

Answer:

$\frac{1}{3}x - 3$