Question

write the electron configuration for a neon cation with a charge of +2.

Explanation:

Step1: Determine the number of electrons in Ne atom

Neon (\(Ne\)) has an atomic number of \(10\), so a neutral \(Ne\) atom has \(10\) electrons.

Step2: Calculate the number of electrons in \(Ne^{2 +}\)

A \(+ 2\) charge means the ion has lost \(2\) electrons. So, the number of electrons in \(Ne^{2+}\) is \(10 - 2=8\) electrons.

Step3: Write the electron configuration for \(8\) electrons

Using the Aufbau principle, the electron configuration is \(1s^{2}2s^{2}2p^{4}\).

Answer:

\(1s^{2}2s^{2}2p^{4}\)