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write $overrightarrow{bc}$ in component form, with $b(6, - 10)$ and $c(…

Question

write $overrightarrow{bc}$ in component form, with $b(6, - 10)$ and $c(9, - 9)$. $overrightarrow{bc}=langlesquare,square
angle$

Explanation:

Step1: Find x - component

Subtract x - coordinates: $9 - 6$.
$9-6 = 3$

Step2: Find y - component

Subtract y - coordinates: $-9-(-10)$.
$-9 - (-10)=-9 + 10=1$

Answer:

$\langle3,1
angle$