Question

write the complete ground - state electron configuration of li^+.for multi - digit superscripts or coefficients, use each number in succession.1s^22s^2incorrect, 3 attempts remaining-0.1 points for incorrect attemptthe electron configuration of an ion is determined by adding or subtracting electrons from electron configuration of the neutral atom. cations are formed by removing electrons from the outermost shell. anions are formed by the addition of electrons to the outermost shell.

Explanation:

Step1: Determine the electron configuration of neutral Li

The atomic number of Li (lithium) is 3. So, the electron configuration of neutral Li is \(1s^{2}2s^{1}\).

Step2: Consider the ion formation

\(Li^{+}\) is formed by losing one electron. Electrons are removed from the outermost shell. The outermost electron in Li is in the \(2s\) orbital. So, after losing one electron, the electron configuration of \(Li^{+}\) is \(1s^{2}\).

Answer:

\(1s^{2}\)