write a 2 - column proof for the following problems.
given: $ \angle adb $ and $ \angle cdb $ are right angles $ \angle a \cong \angle c $
prove: $ \triangle adb=\triangle cdb $

Question

Accepted Answer

# Explanation:
## Step1: State given information
| Statements | Reasons |
| --- | --- |
| $\angle ADB$ and $\angle CDB$ are right angles | Given |
| $\angle A\cong\angle C$ | Given |
## Step2: Use reflexive property
| Statements | Reasons |
| --- | --- |
| $BD = BD$ | Reflexive property of equality (a segment is congruent to itself) |
## Step3: Apply AAS (Angle - Angle - Side) congruence criterion
| Statements | Reasons |
| --- | --- |
| $	riangle ADB\cong	riangle CDB$ | AAS (We have two angles ($\angle A\cong\angle C$, $\angle ADB\cong\angle CDB$ (both right angles)) and a non - included side ($BD$) congruent) |

# Answer:
The two - column proof shows that $	riangle ADB\cong	riangle CDB$ by the AAS congruence criterion.

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QUESTION IMAGE

Question

Explanation:

Step1: State given information

Step2: Use reflexive property

Step3: Apply AAS (Angle - Angle - Side) congruence criterion

Answer: