Question

work - mu
what is the work done for the following scenarios:

• a net force of 5 n is applied to a object as it is displaced 8 m
• a net force of 7 n is applied to a object as it is displaced 2 m

Explanation:

Step1: Recall the formula for work

The formula for work \(W\) is \(W = F\times d\), where \(F\) is the force and \(d\) is the displacement.

Step2: Calculate work for the first scenario

Given \(F = 5\space N\) and \(d=8\space m\). Substitute into the formula: \(W_1=5\times8 = 40\space J\).

Step3: Calculate work for the second scenario

Given \(F = 7\space N\) and \(d = 2\space m\). Substitute into the formula: \(W_2=7\times2=14\space J\).

Answer:

The work done for the first scenario is \(40\space J\) and for the second scenario is \(14\space J\).