Question

words problems: (2 points each)
question

1. what is the momentum of a basketball that has a mass of 1.5kg and is moving with a velocity of 2m/s to the west?
2. what is the mass of an object that has a momentum of 20 kg * m/s that moving with a velocity of 2m/s to the left?
3. what is the velocity of a car moving to the west with a momentum of 3000 kg.m/s if the mass of the car is 500kg?
4. if a car with a mass of 2000kg and a momentum of 60000 kg.km/h hit a stationary wall, what is the resulting momentum after the collision?
5. what is the momentum of a car with a mass of 2500kg parked on top of a 10m hill?

Explanation:

Step1: Recall the formula for momentum

The formula for momentum \(p\) is \(p = mv\), where \(m\) is mass and \(v\) is velocity.

Step2: Substitute the given values for the basketball problem

Given \(m = 1.5\space kg\) and \(v=2\space m/s\). Then \(p=(1.5)(2)\)

$$p = 3\space kg\cdot m/s$$

Step3: For the second problem (mass calculation)

From \(p = mv\), we can solve for \(m\) as \(m=\frac{p}{v}\). Given \(p = 20\space kg\cdot m/s\) and \(v = 2\space m/s\). Then \(m=\frac{20}{2}\)

$$m = 10\space kg$$

Step4: For the third problem (velocity calculation)

From \(p = mv\), solve for \(v\) as \(v=\frac{p}{m}\). Given \(p = 3000\space kg\cdot m/s\) and \(m = 500\space kg\). Then \(v=\frac{3000}{500}\)

$$v=6\space m/s$$

Step5: For the fourth problem (collision with stationary wall)

When a car hits a stationary wall and stops (assuming it comes to rest), its velocity \(v = 0\space m/s\). Using \(p=mv\), with \(v = 0\), \(p=(2000)(0)\)

$$p = 0\space kg\cdot m/s$$

Step6: For the fifth problem (parked car)

A parked car has \(v = 0\space m/s\). Using \(p=mv\), with \(v = 0\), \(p=(m)(0)\)

$$p = 0\space kg\cdot m/s$$

Answer:

1. \(3\space kg\cdot m/s\)
2. \(10\space kg\)
3. \(6\space m/s\)
4. \(0\space kg\cdot m/s\)
5. \(0\space kg\cdot m/s\)