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Question
which is the simplified form of \\(r^{-7} + s^{-12}\\)?
\\(\circ\quad \frac{1}{r^7 s^{12}}\\)
\\(\circ\quad -r^7 - s^{12}\\)
\\(\circ\quad \frac{r^7}{s^{12}}\\)
\\(\circ\quad \frac{1}{r^7} + \frac{1}{s^{12}}\\)
Apply the negative exponent rule
$$
x^{-n} = \frac{1}{x^n}
$$
Rewrite each term individually
$$
r^{-7} = \frac{1}{r^7}
$$
$$
s^{-12} = \frac{1}{s^{12}}
$$
Combine the rewritten terms
$$
r^{-7} + s^{-12} = \frac{1}{r^7} + \frac{1}{s^{12}}
$$
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- (A) \(\frac{1}{r^7 s^{12}}\)
- (B) \(-r^7 - s^{12}\)
- (C) \(\frac{r^7}{s^{12}}\)
- (D) \(\frac{1}{r^7} + \frac{1}{s^{12}}\) (Correct answer)