Question

which set of numbers gives the correct possible values of l for n = 2?
0
0, 1
0, 1, 2
0, 1, 2, 3

Explanation:

Step1: Recall the rule of angular - momentum quantum number

The angular - momentum quantum number $l$ ranges from $0$ to $n - 1$ for a given principal quantum number $n$.

Step2: Calculate the possible values of $l$ for $n = 2$

When $n=2$, $l$ can take values $l = 0$ and $l = 1$ since $l$ starts from $0$ and goes up to $n - 1=2 - 1 = 1$.

Answer:

0, 1