Question

which sample size will produce a margin of error of ±5.4%? 600 202 262 348

Explanation:

Step1: Recall the formula for margin of error

The formula for margin of error \(E\) (when the population proportion \(p = 0.5\)) is \(E=\frac{1}{\sqrt{n}}\), where \(n\) is the sample size. We are given \(E = 0.054\).

Step2: Solve for \(n\)

From \(E=\frac{1}{\sqrt{n}}\), we can rewrite it as \(\sqrt{n}=\frac{1}{E}\). Substituting \(E = 0.054\), we get \(\sqrt{n}=\frac{1}{0.054}\approx18.52\). Then \(n=(18.52)^{2}\approx343\).

Answer:

348