QUESTION IMAGE
Question
which piecewise function best describes the scenario below?
a shipping company charges for shipping based on weight of package:
- for packages weighing up to 5 pounds, the cost is $4.
- for packages weighing more than 5 but less than 10 pounds, the cost is $8.
- for packages weighing 10 pounds or more, the cost is $12.
option 1:
\\( f(x) = \
$$\begin{cases} 4 & 0 \\le x \\le 5 \\\\ 8 & 5 < x < 10 \\\\ 12 & x \\ge 10 \\end{cases}$$
\\)
option 2:
\\( f(x) = \
$$\begin{cases} 4 & 0 \\le x \\le 5 \\\\ 8 & 5 \\le x \\le 10 \\\\ 12 & x \\ge 10 \\end{cases}$$
\\)
option 3:
\\( f(x) = \
$$\begin{cases} 4 & 0 < x < 5 \\\\ 8 & 5 < x < 10 \\\\ 12 & x > 10 \\end{cases}$$
\\)
option 4:
\\( f(x) = \
$$\begin{cases} 12 & 0 \\le x \\le 5 \\\\ 8 & 5 < x < 10 \\\\ 4 & x \\ge 10 \\end{cases}$$
\\)
Translate the first condition into an inequality
Using the Piecewise Functions knowledge point
- "Up to 5 pounds" means the weight \(x\) is greater than or equal to 0 and less than or equal to 5.
- This corresponds to the interval \(0 \le x \le 5\) with a cost of 4.
Translate the second condition into an inequality
Using the Piecewise Functions knowledge point
- "More than 5 but less than 10 pounds" means the weight \(x\) is strictly greater than 5 and strictly less than 10.
- This corresponds to the interval \(5 < x < 10\) with a cost of 8.
Translate the third condition into an inequality
Using the Piecewise Functions knowledge point
- "10 pounds or more" means the weight \(x\) is greater than or equal to 10.
- This corresponds to the interval \(x \ge 10\) with a cost of 12.
Match the intervals to the options
Using the Piecewise Functions knowledge point
- Combining these three intervals gives:
$$
F(x) =
LATEXBLOCK0
$$
- This matches the first option.
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- **(A) \(F(x) =
$$\begin{cases} 4 & 0 \le x \le 5 \\ 8 & 5 < x < 10 \\ 12 & x \ge 10 \end{cases}$$
\) (Correct answer)**
- (B) \(F(x) =
$$\begin{cases} 4 & 0 \le x \le 5 \\ 8 & 5 \le x \le 10 \\ 12 & x \ge 10 \end{cases}$$
\)
- (C) \(F(x) =
$$\begin{cases} 4 & 0 < x < 5 \\ 8 & 5 < x < 10 \\ 12 & x > 10 \end{cases}$$
\)
- (D) \(F(x) =
$$\begin{cases} 12 & 0 \le x \le 5 \\ 8 & 5 < x < 10 \\ 4 & x \ge 10 \end{cases}$$
\)