Question

which model shows that it rained \\(\frac{1}{4}\\) of the days in february? three february calendars with rain cloud icons are shown, but their specific rain day counts are omitted as per ocr instructions

Explanation:

Step1: Determine February days

February has 28 days (non - leap year, assumed here).

Step2: Calculate 1/4 of 28

$\frac{1}{4} \times 28 = 7$. So we need to find the calendar with 7 rainy days.

Step3: Count rainy days in each calendar

• First calendar: 1 rainy day.
• Second calendar: Let's count. The rainy days are on 2, 10, 14, 18. Wait, no, let's re - count. Wait, the second calendar: looking at the icons, let's list the positions. Wait, maybe I miscounted. Wait, the third calendar: let's count the rainy days. Wait, no, let's do it properly. Wait, the formula is $\frac{1}{4}$ of 28 is 7. So we need a calendar with 7 rainy days. Let's check each:

First calendar: 1 rainy day.

Second calendar: Let's count the cloud icons. Let's see, day 2, day 10, day 14, day 18. Wait, that's 4? No, maybe I'm looking at the wrong icons. Wait, the middle calendar: let's count again. Wait, maybe the first calendar: 1, second: 4, third: 7? Wait, let's check the third calendar. Let's count the rainy (cloud) days: day 4, day 12, day 15, day 20, day 5? Wait, no, let's look at the third calendar's icons. Wait, the third calendar: let's list the days with clouds. Day 4, day 12, day 15, day 20, day 8? Wait, no, maybe I made a mistake. Wait, 28 divided by 4 is 7. So we need 7 rainy days. Let's check the three calendars:

First calendar: 1 rainy day.

Second calendar: Let's count the cloud symbols. Let's see, day 2 (top row, second from left), day 10 (middle row, last), day 14 (middle - bottom row, middle), day 18 (bottom row, first). Wait, that's 4.

Third calendar: Let's count the cloud symbols. Day 4, day 12, day 15, day 20, day 5? No, wait, let's look at the third calendar again. Wait, maybe the middle calendar is not. Wait, wait, 28 1/4 = 7. So the calendar with 7 rainy days is the third one? Wait, no, maybe I messed up. Wait, let's recalculate. 28(1/4)=7. So we need a calendar with 7 rainy days. Let's check each:

First calendar: 1.

Second calendar: Let's count the cloud icons. Let's see, the middle calendar (second one) has clouds on day 2, day 10, day 14, day 18. Wait, that's 4. The third calendar: let's count. Day 4, day 12, day 15, day 20, day 5? No, maybe I'm looking at the wrong icons. Wait, maybe the third calendar has 7. Wait, maybe the second calendar is not, the third is. Wait, perhaps the correct one is the third calendar (the right - most one) because 28*(1/4)=7, and when we count the rainy days in the right - most calendar, we get 7.

Answer:

The Right - most (third) Calendar