Question

which is the image of ( p(-5,11) ) along the vector ( <3,-8> )?
a) ( p(-8,19) )
b) ( p(-8,3) )
c) ( p(-2,-3) )
d) ( p(-2,3) )

Explanation:

Step1: Add the x - coordinates

To find the x - coordinate of the image \(P'\), add the x - coordinate of the vector to the x - coordinate of point \(P\).
\(x\) - coordinate of \(P=-5\), \(x\) - coordinate of vector \( = 3\)
\(-5+3=-2\)

Step2: Add the y - coordinates

To find the y - coordinate of the image \(P'\), add the y - coordinate of the vector to the y - coordinate of point \(P\).
\(y\) - coordinate of \(P = 11\), \(y\) - coordinate of vector \(=-8\)
\(11+( - 8)=11 - 8 = 3\)

Answer:

D. \(P'(-2,3)\)