Question

which of the following options best completes the column for (!x || y) && (x || y) in the truth table? x y!x||y x||y (!x||y) && (x||y) t t t t f f t t f f ?

Explanation:

Step1: Calculate \(!x\)

When \(x = F\), \(!x=T\).

Step2: Calculate \(!x||y\)

Since \(x = F,y = F\), then \(!x=T\), and \(T||F=T\).

Step3: Calculate \(x||y\)

Since \(x = F,y = F\), then \(F||F=F\).

Step4: Calculate \((!x||y)\&\&(x||y)\)

Since \(!x||y=T\) and \(x||y = F\), then \(T\&\&F=F\).

Answer:

\(F\)