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which of the following explanations outlines an incomplete combustion r…

Question

which of the following explanations outlines an incomplete combustion reaction? a hydrocarbon reacts with oxygen to form carbon dioxide and water vapour. carbon monoxide reacts with oxygen to form carbon dioxide. a hydrocarbon reacts with oxygen to form solid carbon, carbon monoxide, and water vapour. a hydrocarbon does not reacts with oxygen what is the balanced chemical equation for the single displacement reaction of fluorine in an aqueous solution of lithium bromide? image of a document with options a, b, c, d a. 2libr(aq) + f₂ ⟶ 2lif(aq) + br₂ b. libr(aq) + f₂ ⟶ lif(aq) + br₂ c. 2libr(aq) + f₂ ⟶ 2fbr(aq) + 2li d. the reaction does not occur a b c d

Explanation:

First Sub - Question (Incomplete Combustion Reaction)
Brief Explanations

In complete combustion of a hydrocarbon, the products are \(CO_2\) and \(H_2O\). In incomplete combustion, due to insufficient oxygen, products like solid carbon (soot), \(CO\) (along with \(H_2O\)) are formed. The first option is complete combustion, the second is a reaction of \(CO\) (not a hydrocarbon combustion), and the fourth is incorrect as hydrocarbons do react with oxygen.

Second Sub - Question (Balanced Chemical Equation for Single Displacement)

Step 1: Recall Single Displacement Rules

In a single - displacement reaction, a more reactive element displaces a less reactive element from its compound. Fluorine (\(F_2\)) is more reactive than bromine (\(Br_2\)) (based on the activity series of halogens). So, \(F_2\) will displace \(Br^-\) from \(LiBr\).

Step 2: Balance the Equation

  • For Lithium: On the left - hand side, in \(LiBr\), if we have 2 moles of \(LiBr\), we have 2 moles of \(Li\). On the right - hand side, in \(LiF\), to balance \(Li\), we need 2 moles of \(LiF\).
  • For Bromine: On the left - hand side, 2 moles of \(LiBr\) give 2 moles of \(Br\). On the right - hand side, \(Br_2\) has 2 moles of \(Br\) (since \(Br_2\) is diatomic), so bromine is balanced.
  • For Fluorine: On the left - hand side, 1 mole of \(F_2\) (2 moles of \(F\)) and on the right - hand side, 2 moles of \(LiF\) have 2 moles of \(F\), so fluorine is balanced.

Option b is unbalanced (only 1 mole of \(LiBr\) on the left, but products have \(Br_2\) which needs 2 moles of \(Br\) from \(LiBr\)). Option c has an incorrect product (\(FBr\) is not formed, and \(Li\) is not displaced in this way). So the correct balanced equation is \(2LiBr_{(aq)}+F_2\longrightarrow2LiF_{(aq)} + Br_2\).

Answer:

A hydrocarbon reacts with oxygen to form solid carbon, carbon monoxide, and water vapour.