Question

which of the following atom(s) below has/have five valence electrons?
answer:
a c
b n
c o
d f

Explanation:

• For element \(C\) (Carbon), the electron configuration is \(1s^{2}2s^{2}2p^{2}\). The number of valence electrons is \(4\) (from \(2s^{2}2p^{2}\)).
• For element \(N\) (Nitrogen), the electron configuration is \(1s^{2}2s^{2}2p^{3}\). The number of valence electrons is \(5\) (from \(2s^{2}2p^{3}\)).
• For element \(O\) (Oxygen), the electron configuration is \(1s^{2}2s^{2}2p^{4}\). The number of valence electrons is \(6\) (from \(2s^{2}2p^{4}\)).
• For element \(F\) (Fluorine), the electron configuration is \(1s^{2}2s^{2}2p^{5}\). The number of valence electrons is \(7\) (from \(2s^{2}2p^{5}\)).

Answer:

B. N