Question

which equation represents the relationship between x and y?
a y = 0.25x
b y = 0.50x
c y = 0.75x
d y = 1.50x
apply the equation found in question 1 to compute the time it would take to cook a 12-pound beef roast.
a 4
b 6
c 8

Explanation:

Step1: Analyze the first question (equation relationship)

Assuming typical cooking time for beef (e.g., if we consider common ratios, but since we need to match the options, let's check the second question. For a 12 - pound roast, let's test the equations. Let's take option C: \(y = 0.75x\). If \(x = 12\), \(y=0.75\times12 = 9\) (not in options). Wait, maybe the first question's correct equation is \(y = 0.75x\)? Wait, no, the second question's options are 4,6,8. Let's check option A: \(y = 0.25x\), \(x = 12\), \(y = 3\) (no). Option B: \(y=0.5x\), \(x = 12\), \(y = 6\) (matches option B in second question). Wait, maybe I made a mistake. Wait, the first question: let's assume that in the original context (maybe a table or graph not shown), but since the second question has 6 as an option, and \(y = 0.5x\) gives \(x = 12\), \(y=6\). So first question: B. \(y = 0.50x\), second question: B. 6.

Step1 (First Question):

We need to find the equation \(y = kx\) (proportional relationship). To determine \(k\), we can use the second question. The second question is about a 12 - pound roast. Let's test each equation with \(x = 12\):

• For A: \(y=0.25\times12 = 3\) (not in second question options).
• For B: \(y = 0.5\times12=6\) (matches option B in second question).
• For C: \(y = 0.75\times12 = 9\) (not in options).
• For D: \(y = 1.5\times12 = 18\) (not in options).

So the correct equation for the first question is \(y = 0.50x\) (option B).

Step2 (Second Question):

Now, apply \(y = 0.50x\) with \(x = 12\) (12 - pound roast). So \(y=0.5\times12 = 6\).

Answer:

First Question: B. \(y = 0.50x\)
Second Question: B. 6