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Question
which equation is the inverse of (y = x^2 + 16)?
- (y = x^2 - 16)
- (y = \pm\sqrt{x} - 16)
- (y = \pm\sqrt{x - 16})
- (y = x^2 - 4)
Swap variables to find the inverse relation
$$
x = y^2 + 16
$$
Solve for y
$$
LATEXBLOCK0
$$
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- \(y = x^2 - 16\)
- \(y = \pm\sqrt{x} - 16\)
- \(y = \pm\sqrt{x - 16}\) (Correct answer)
- \(y = x^2 - 4\)