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Question
which congruence theorem can be used to prove △bda ≅ △dbc?
options: hl, sas, aas, sss
Step1: Identify the triangles as right - angled
$\triangle BDA$ and $\triangle DBC$ are right - angled triangles (right angles at the marked vertices).
Step2: Check the hypotenuse and leg
The hypotenuse ($BD$ is common to both triangles, so hypotenuse is equal) and one leg (the marked equal sides in the diagram). By the Hypotenuse - Leg (HL) congruence theorem for right - angled triangles, $\triangle BDA\cong\triangle DBC$.
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HL