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QUESTION IMAGE

which angles are vertical angles? image of lines and angles with points…

Question

which angles are vertical angles? image of lines and angles with points p, m, s, q, n, l, r, o options: ∠mnq and ∠onq; ∠mnq and ∠onl; ∠mnq and ∠rqn; ∠mnq and ∠pqs

Explanation:

Step1: Recall Vertical Angles Definition

Vertical angles are formed by two intersecting lines and are opposite each other, sharing a common vertex but no common side.

Step2: Analyze Each Option

  • Option 1: $\angle MNQ$ and $\angle ONQ$ share a common side $NQ$, not vertical angles.
  • Option 2: $\angle MNQ$ and $\angle ONL$: $\angle ONL$ is related to line $NL$, not opposite to $\angle MNQ$.
  • Option 3: $\angle MNQ$ and $\angle RQN$: Lines $PM$ and $RO$ intersect with line $SL$? Wait, actually, lines $PR$ and $MO$ intersect with line $SL$? Wait, no, looking at the diagram, lines $PR$ (with points $P, Q, R$) and $MO$ (with points $M, N, O$) are two lines, and line $SL$ (with points $S, Q, N, L$) is a transversal? Wait, no, actually, when two lines intersect, vertical angles are opposite. Wait, $\angle MNQ$: vertex at $N$? Wait, no, $\angle MNQ$: vertex at $N$? Wait, $\angle RQN$: vertex at $Q$? Wait, no, maybe I misread. Wait, $\angle MNQ$: points $M, N, Q$ – so vertex at $N$, sides $NM$ and $NQ$. $\angle RQN$: points $R, Q, N$ – vertex at $Q$? No, wait, no, $\angle RQN$: vertex at $Q$, sides $RQ$ and $QN$. Wait, no, maybe the lines $PR$ ( $P - Q - R$ ) and $MO$ ( $M - N - O$ ) intersect with line $SQNL$ ( $S - Q - N - L$ ). So at point $Q$, lines $PR$ and $SQNL$ intersect? At point $N$, lines $MO$ and $SQNL$ intersect. Wait, no, vertical angles are formed when two lines intersect. So if we consider lines $PR$ ( $PQR$ ) and $MO$ ( $MNO$ ) intersecting? Wait, no, they don't intersect. Wait, line $SQNL$ is a straight line ( $S - Q - N - L$ ). Line $PR$ is $P - Q - R$, line $MO$ is $M - N - O$. So at point $Q$, line $PR$ and line $SQNL$ intersect, forming angles. At point $N$, line $MO$ and line $SQNL$ intersect, forming angles. Wait, but vertical angles should be from two intersecting lines. Wait, maybe $\angle MNQ$ and $\angle RQN$: let's check the vertices. $\angle MNQ$: vertex $N$, sides $NM$ and $NQ$. $\angle RQN$: vertex $Q$, sides $RQ$ and $QN$. Wait, no, maybe I made a mistake. Wait, another approach: vertical angles are equal and opposite. Let's see the diagram: line $PR$ (up and down: $P$ up, $R$ down) and line $MO$ (up and down: $M$ up, $O$ down) are parallel? No, they are two lines, and line $SQNL$ is horizontal ( $S$ left, $L$ right). So at point $Q$, line $PR$ (vertical) and line $SQNL$ (horizontal) intersect, forming $\angle PQS$ (top left), $\angle SQR$ (bottom left), $\angle RQN$ (bottom right), $\angle PQN$ (top right)? Wait, no, at point $Q$, lines $PR$ (vertical) and $SQNL$ (horizontal) intersect, so the four angles: $\angle PQS$ ( $P - Q - S$ ), $\angle SQR$ ( $S - Q - R$ ), $\angle RQN$ ( $R - Q - N$ ), $\angle NQP$ ( $N - Q - P$ ). At point $N$, lines $MO$ (vertical) and $SQNL$ (horizontal) intersect, forming $\angle MNS$ (no, $M - N - S$? No, $M - N - L$? Wait, $\angle MNQ$: $M - N - Q$ – so at point $N$, line $MO$ ( $M - N - O$ ) and line $SQNL$ ( $S - Q - N - L$ ) intersect, so $\angle MNQ$ is $M - N - Q$ (top left at $N$), and the vertical angle would be the angle opposite, which is $\angle ONL$? No, wait, no. Wait, maybe the correct pair is $\angle MNQ$ and $\angle RQN$ because when lines $PR$ and $MO$ are considered, but no, they are not intersecting. Wait, maybe I messed up the angle labels. Let's re-express: $\angle MNQ$: vertex $N$, sides $NM$ and $NQ$. $\angle RQN$: vertex $Q$, sides $RQ$ and $QN$. Wait, no, that can't be. Wait, maybe the diagram has lines $PR$ ( $P, Q, R$ ) and $MO$ ( $M, N, O$ ) as two lines, and line $SL$ ( $S, Q, N, L$ ) as a transversal. So at $Q$, $\angle RQN$ is formed by $RQ$…

Answer:

$\angle MNQ$ and $\angle RQN$