Question

what is the volume of a sphere with a radius of 60.5 ft, rounded to the nearest tenth of a cubic foot?

Explanation:

Step1: Write the formula for the volume of a sphere

The formula for the volume \(V\) of a sphere is \(V=\frac{4}{3}\pi r^{3}\), where \(r\) is the radius of the sphere.

Step2: Substitute the given radius into the formula

Given \(r = 60.5\) ft. First, calculate \(r^{3}\): \(r^{3}=(60.5)^{3}=60.5\times60.5\times60.5 = 221963.125\).
Then, find \(\frac{4}{3}\pi r^{3}\): \(V=\frac{4}{3}\times\pi\times221963.125\).
\(V=\frac{4\times\pi\times221963.125}{3}\).
\(4\times\pi\times221963.125\approx4\times3.14159\times221963.125\approx2789040.7\).
\(V=\frac{2789040.7}{3}\approx929680.2\).

Answer:

\(929680.2\) cubic feet.