Question

what volume, in ml, of 6.30 m h₂so₄ is needed to prepare 35.50 ml of a solution that is 0.340 m in h₂so₄? report your answer with the correct number of significant figures.

Explanation:

Step1: Use dilution formula

The dilution formula is \(C_1V_1 = C_2V_2\), where \(C_1\) is the initial concentration, \(V_1\) is the initial volume, \(C_2\) is the final concentration, and \(V_2\) is the final volume.
Given \(C_1 = 6.30\space M\), \(C_2=0.340\space M\), \(V_2 = 35.50\space mL\). We need to find \(V_1\).
Rearrange the formula to \(V_1=\frac{C_2V_2}{C_1}\).

Step2: Substitute values

Substitute the values into the formula: \(V_1=\frac{0.340\space M\times35.50\space mL}{6.30\space M}\).
First, calculate the numerator: \(0.340\times35.50 = 12.07\).
Then, divide by \(6.30\): \(V_1=\frac{12.07}{6.30}\approx1.92\space mL\).

Answer:

\(1.92\space mL\)