Question

what volume, in liters, of 4.0 m libr solution can be made using 100.0 g libr? libr: 86.44 g/mol

Explanation:

Step1: Calculate moles of LiBr

Moles = $\frac{\text{Mass}}{\text{Molar Mass}}$. Mass of LiBr is 100.0 g, molar mass is 86.44 g/mol. So moles = $\frac{100.0\ \text{g}}{86.44\ \text{g/mol}} \approx 1.157\ \text{mol}$.

Step2: Use molarity formula to find volume

Molarity ($M$) = $\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$. Rearranged, Volume = $\frac{\text{Moles}}{M}$. Moles is 1.157 mol, $M$ is 4.0 M. So Volume = $\frac{1.157\ \text{mol}}{4.0\ \text{mol/L}} \approx 0.289\ \text{L}$.

Answer:

$\approx 0.289$