Question

what volume (in liters) does 3.91 moles of nitrogen gas at 4,066 torr and 323 k occupy? g: n = 3.91 mol e: pv = nrt p = 4,066 torr *use r = t = 323 k 62.4 \frac{l\cdot torr}{mol\cdot k} u: v = ? l

Explanation:

Step1: Rearrange ideal gas law for V

$V = \frac{nRT}{P}$

Step2: Substitute given values

$V = \frac{(3.91\ \text{mol})(62.4\ \frac{\text{L·torr}}{\text{mol·K}})(323\ \text{K})}{4066\ \text{torr}}$

Step3: Calculate numerator

$3.91×62.4×323 ≈ 3.91×20155.2 ≈ 78806.832$

Step4: Divide by pressure

$V ≈ \frac{78806.832}{4066} ≈ 19.4$

Answer:

19.4