Question

what values of b and c make \\( \triangle fgh cong \triangle kij \\)?

Explanation:

Step1: Find the value of \( b \)

Since \( \triangle FGH\cong\triangle KIJ \), corresponding sides are equal. So \( FG = KI \), which gives the equation \( b + 40=5b \).
Subtract \( b \) from both sides: \( 40 = 5b - b \), so \( 40=4b \).
Divide both sides by \( 4 \): \( b=\frac{40}{4}=10 \).

Step2: Find the value of \( c \)

Also, \( FH = KJ \). So \( c + 8=2c \).
Subtract \( c \) from both sides: \( 8=2c - c \), so \( c = 8 \).

Answer:

\( b = 10 \), \( c = 8 \)