what value(s) of $x$ make the equation $x^2 - 18x + 81 = 0$ true?

- 9
- -9, 9
- 0, 9
- 0, -9, 9

Question

what value(s) of $x$ make the equation $x^2 - 18x + 81 = 0$ true?

- 9
- -9, 9
- 0, 9
- 0, -9, 9

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "multiple_choice_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Solving Quadratic Equations" ], "new_concepts": [], "current_concepts": [ "Solving Quadratic Equations", "Zeros of Quadratic Functions" ] } ## Identify the quadratic equation $$ x^2 - 18x + 81 = 0 $$ ## Factor the perfect square trinomial $$ (x - 9)^2 = 0 $$ ## Solve for x $$ \begin{aligned} x - 9 &= 0 \ x &= 9 \end{aligned} $$

(A) 9

(B) -9, 9

(C) 0, 9

(D) 0, -9, 9

{ "subject": "Mathematics", "question_type": "Multiple Choice", "knowledge_point": [ "Mathematics", "Algebra", "Solving Quadratic Equations" ] }

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QUESTION IMAGE

Question

Explanation:

Identify the quadratic equation

Factor the perfect square trinomial

Solve for x

Answer: