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in $\triangle jkl$, $mangle j=(8x - 8)^{circ}$, $mangle k=(2x - 8)^{cir…

Question

in $\triangle jkl$, $mangle j=(8x - 8)^{circ}$, $mangle k=(2x - 8)^{circ}$, and $mangle l=(5x - 14)^{circ}$. what is the value of $x$?

Explanation:

Step1: Recall angle - sum property

The sum of angles in a triangle is 180°. So, $(8x - 8)+(2x - 8)+(5x - 14)=180$.

Step2: Combine like - terms

$8x+2x + 5x-8-8 - 14=180$, which simplifies to $15x-30 = 180$.

Step3: Solve for x

Add 30 to both sides: $15x=210$. Then divide by 15: $x = 14$.

Answer:

14