Question

what type of reaction involves multiple reactants forming one product? * 2 points
decomposition
synthesis
combustion
single replacement

what type of reaction always has the products of co₂ and h₂o ? * 2 points
single replacement
synthesis
combustion
decomposition

balance the following equation: _ n₂ + _ o₂ → ___ n₂o₅ * 2 points
n₂ + 3o₂ → 2n₂o₅
2n₂ + 5o₂ → 2n₂o₅
4n₂ + 5o₂ → 4n₂o₅
n₂ + 5o₂ → 2n₂o₅

Explanation:

First Question:

• Decomposition: One reactant breaks into multiple products. Eliminate.
• Synthesis: Multiple reactants combine to form one product (general form: \( A + B

ightarrow AB \)). This matches the description.

• Combustion: Involves a fuel reacting with oxygen, products vary but often include \( CO_2 \) and \( H_2O \), not just forming one product from multiple reactants in the general sense of synthesis. Eliminate.
• Single Replacement: One element replaces another in a compound (e.g., \( A + BC

ightarrow AC + B \)), has multiple products. Eliminate.

• Single Replacement: Involves element replacement, products are a new compound and element, not always \( CO_2 \) and \( H_2O \). Eliminate.
• Synthesis: Multiple reactants form one product, products not limited to \( CO_2 \) and \( H_2O \). Eliminate.
• Combustion: A reaction where a hydrocarbon (or similar) reacts with \( O_2 \), and the products are always \( CO_2 \) and \( H_2O \) (for hydrocarbon combustion). This matches.
• Decomposition: One reactant breaks down, products not \( CO_2 \) and \( H_2O \) always. Eliminate.

Step1: Count N and O atoms

• Reactants: \( N_2 \) (2 N), \( O_2 \) (2 O)
• Products: \( N_2O_5 \) (2 N, 5 O) per molecule.

Step2: Balance O first

• Let coefficients be \( aN_2 + bO_2

ightarrow cN_2O_5 \)

• O: \( 2b = 5c \). Find least common multiple of 2 and 5, which is 10. So \( b = 5 \), \( c = 2 \).

Step3: Balance N

• N: \( 2a = 2c \). Since \( c = 2 \), \( a = 2 \).
• So equation: \( 2N_2 + 5O_2

ightarrow 2N_2O_5 \)

Answer:

B. Synthesis

Second Question: