Question

what is the systemic name for tiso₄?
a) titanium sulfide
b) titanium(iv) sulfide
c) titanium sulfate
d) titanium(ii) sulfate
e) titanium(ii) sulfur

Explanation:

• First, identify the anion. In \(TiSO_4\), the anion is \(SO_4^{2 -}\), which is the sulfate ion. So the compound is a sulfate, not a sulfide (eliminates options a and b).
• Then, determine the oxidation state of titanium (\(Ti\)). For the compound \(TiSO_4\), since the sulfate ion (\(SO_4^{2 -}\)) has a charge of - 2, and the compound is neutral. Let the oxidation state of \(Ti\) be \(x\). Using the charge balance rule \(x+(-2)=0\), we get \(x = + 2\). So the oxidation state of \(Ti\) is \(+2\), and we use the Roman numeral (II) in the name.

Answer:

d) titanium(II) sulfate