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Question
what is the size of each of the exterior angles of a regular 18-sided polygon?
⚡ Using what you learned: properties of polygons
Step 1: Identify the sum of exterior angles
The sum of the exterior angles of any convex polygon is always \( 360^\circ \).
Step 2: Calculate the size of each exterior angle
For a regular polygon with \( n \) sides, all exterior angles are equal. Divide the sum by the number of sides, where \( n = 18 \):
$$ \text{Exterior Angle} = \frac{360^\circ}{18} $$
$$ \text{Exterior Angle} = 20^\circ $$
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\( 20^\circ \)