QUESTION IMAGE
Question
what is \frac{\sqrt{25x^2y^2}}{\sqrt{xy}} in simplest form? assume x \ge 0 and y \ge 0.
- 5\sqrt{xy}
- 25\sqrt{xy}
- \sqrt{5xy}
- 5xy\sqrt{xy}
Apply the quotient property of radicals
Using the Quotient Property of Radicals knowledge point
$$
\frac{\sqrt{25x^2y^2}}{\sqrt{xy}} = \sqrt{\frac{25x^2y^2}{xy}}
$$
Simplify the expression inside the radical
Using the Radical Simplification knowledge point
$$
\sqrt{\frac{25x^2y^2}{xy}} = \sqrt{25xy}
$$
Extract perfect squares from the radical
Using the Radical Simplification knowledge point
$$
\sqrt{25xy} = \sqrt{25} \cdot \sqrt{xy} = 5\sqrt{xy}
$$
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- (A) \(5\sqrt{xy}\) (Correct answer)
- (B) \(25\sqrt{xy}\)
- (C) \(\sqrt{5xy}\)
- (D) \(5xy\sqrt{xy}\)