Question

what will be printed when we run the following code snippet and the user enters 0?
type your response
try:
userinput = input(\enter an int >0: \)
value = 10/int(userinput)
print(1, end = \ \)
except valueerror:
print(2, end = \ \)
except zerodivisionerror:
print(3, end = \ \)
else:
print(4, end = \ \)
finally:
print(5, end = \ \)

Explanation:

Step1: Analyze the code

The code tries to take user input, convert it to an integer, and perform division. If there's an error, it catches specific exceptions.

Step2: Check for ZeroDivisionError

When user enters '0', int(userInput) is 0. Then 10 / 0 causes a ZeroDivisionError.

Step3: Execute the except block

The except ZeroDivisionError block prints 3.

Step4: Execute the finally block

The finally block always executes (regardless of whether an exception occurred or not) and prints 5.

Answer:

3 5