what is the ph of the 0.24 m strong acid solution?

0.62
0.24
13.38

Question

what is the ph of the 0.24 m strong acid solution?

0.62
0.24
13.38

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "multiple_choice_formatter", "explain_then_answer", "tutor", "mastery_adaptive_brevity" ], "needs_drawing": false, "concepts_used": [ "Strong Acid Dissociation" ], "new_concepts": [ "pH Calculation" ], "current_concepts": [ "Strong Acid Dissociation", "pH Calculation" ] } ## Identify hydronium concentration Using the *Strong Acid Dissociation* knowledge point $$ \begin{aligned} &\text{HA} ightarrow \text{H}^+ + \text{A}^-\ &[\text{H}^+] = C_a = 0.24\text{ M} \end{aligned} $$ ## Calculate pH value Using the *pH Calculation* knowledge point, we find the negative logarithm of the hydronium ion concentration: $$ \begin{aligned} \text{pH} &= -\log_{10}[\text{H}^+] \ \text{pH} &= -\log_{10}(0.24) \ \text{pH} &\approx -(-0.6198) \approx 0.62 \end{aligned} $$

(A) 0.62

(B) 0.24

(C) 13.38

{ "subject": "Natural Science", "question_type": "Multiple Choice", "knowledge_point": [ "Natural Science", "Chemistry", "pH Calculation" ] }

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Question

Explanation:

Identify hydronium concentration

Calculate pH value

Answer: