Question

what is the percent composition of c₂h₂? (molar masses to use: c=12.011 and h=1.008)
a c=92.26%
b c=12.011%
c c=24.02%
d h=1.008%
e h=7.74%
f h=2.01%

Explanation:

Step1: Calculate molar mass of \( C_2H_2 \)

Molar mass \( = (2 \times 12.011) + (2 \times 1.008) \)
\( = 24.022 + 2.016 = 26.038 \)

Step2: Calculate percent composition of C

Percent of C \( = \frac{2 \times 12.011}{26.038} \times 100\% \)
\( = \frac{24.022}{26.038} \times 100\% \approx 92.26\% \)

Step3: Calculate percent composition of H

Percent of H \( = \frac{2 \times 1.008}{26.038} \times 100\% \)
\( = \frac{2.016}{26.038} \times 100\% \approx 7.74\% \)

Answer:

For Carbon (C): A. C = 92.26%
For Hydrogen (H): E. H = 7.74%