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what is the part of the em spectrum of visible light has the most energ…

Question

what is the part of the em spectrum of visible light has the most energy & therefor refracts less?

Explanation:

Brief Explanations

In the visible light spectrum, energy is related to frequency (and inversely to wavelength) by \( E = hf \) (Planck's equation, where \( E \) is energy, \( h \) is Planck's constant, \( f \) is frequency). Violet light has the highest frequency (shortest wavelength) in visible light, so it has the most energy. For refraction, higher - energy (higher - frequency) visible light like violet refracts more? Wait, no, the question says "refracts less"? Wait, maybe a confusion. Wait, in a prism, violet light bends (refracts) more than red. But the question says "refracts less"? Wait, maybe the question has a typo or I misread. Wait, the visible spectrum: red has longest wavelength, lowest frequency, least energy; violet has shortest wavelength, highest frequency, most energy. In terms of refraction in a medium (like a prism), the refractive index generally increases with frequency for visible light, so violet (higher frequency) refracts more (bends more) than red. But the question says "refracts less"? Maybe the question meant "refracts more"? Or maybe a different context. But based on energy: violet has most energy. So the answer is violet.

Answer:

violet