Question

what is the new volume when an expandable 4.51 l container of gas at 273 k is warmed to 546 k?
v = ? l
assume that the number of moles and the pressure remain constant.

Explanation:

Step1: Recall Charles's Law formula

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$ (constant n, P)

Step2: Identify known values

$V_1=4.51\ \text{L}, T_1=273\ \text{K}, T_2=546\ \text{K}$

Step3: Solve for $V_2$

$V_2 = V_1 \times \frac{T_2}{T_1} = 4.51 \times \frac{546}{273}$

Step4: Calculate result

$V_2 = 4.51 \times 2 = 9.02\ \text{L}$

Answer:

9.02 L