Question

what is the molarity of a solution prepared using the given amount of solute and total volume of solution?
part 1 of 2
7.9 mol of naoh in 6.10 l of solution. be sure your answer has the correct number of significant
figures.
m naoh
part 2 of 2
43.7 g of nano₃ in 480. ml of solution. be sure your answer has the correct number of significant
figures.
m nano₃

Explanation:

Part 1 of 2

Step1: Recall the formula for molarity

Molarity \(M=\frac{n}{V}\), where \(n\) is the number of moles of solute and \(V\) is the volume of solution in liters.
Given \(n = 7.9\space mol\) and \(V=6.10\space L\)

Step2: Substitute the values into the formula

\(M=\frac{7.9\space mol}{6.10\space L}\)
\(M = 1.29508\space mol/L\approx1.3\space M\) (rounded to two significant figures as \(7.9\) has two significant figures)

Part 2 of 2

Step1: Calculate the molar mass of \(NaNO_3\)

The molar mass of \(NaNO_3\): \(M_{NaNO_3}=22.99 + 14.01+3\times16.00=85.00\space g/mol\)

Step2: Calculate the number of moles of \(NaNO_3\)

\(n=\frac{m}{M}\), where \(m = 43.7\space g\) and \(M = 85.00\space g/mol\)
\(n=\frac{43.7\space g}{85.00\space g/mol}=0.514118\space mol\)

Step3: Convert the volume of solution to liters

\(V = 480\space mL=480\times10^{- 3}\space L = 0.480\space L\)

Step4: Calculate the molarity

Using \(M=\frac{n}{V}\), substitute \(n = 0.514118\space mol\) and \(V = 0.480\space L\)
\(M=\frac{0.514118\space mol}{0.480\space L}=1.07108\space mol/L\approx1.07\space M\) (rounded to three significant figures as \(43.7\) has three significant figures)

Answer:

Part 1 of 2: \(1.3\space M\space NaOH\)
Part 2 of 2: \(1.07\space M\space NaNO_3\)